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4.905t^2-8.08t+.65=0
We add all the numbers together, and all the variables
4.905t^2-8.08t+0.65=0
a = 4.905; b = -8.08; c = +0.65;
Δ = b2-4ac
Δ = -8.082-4·4.905·0.65
Δ = 52.5334
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8.08)-\sqrt{52.5334}}{2*4.905}=\frac{8.08-\sqrt{52.5334}}{9.81} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8.08)+\sqrt{52.5334}}{2*4.905}=\frac{8.08+\sqrt{52.5334}}{9.81} $
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